作出下列对数函数图像的图像(1)y=x-1,x...

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>>>作出函数f(x)=|x-2|-|x+1|的图象,并由图象求f(x)的值域.-高一数..
作出函数f(x)=|x-2|-|x+1|的图象,并由图象求f(x)的值域.
题型:解答题难度:中档来源:同步题
解:当x<-1时,f(x)=-(x-2)-[-(x+1)]=3;当-1≤x≤2时, f(x)=-(x-2)-(x+1)=-2x+1;当x>2时,f(x)=(x-2)-(x+1)=-3,∴f(x)=,f(x)的图象如下图所示,由函数图象知,函数的值域为[-3,3]。
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据魔方格专家权威分析,试题“作出函数f(x)=|x-2|-|x+1|的图象,并由图象求f(x)的值域.-高一数..”主要考查你对&&分段函数与抽象函数&&等考点的理解。关于这些考点的“档案”如下:
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因为篇幅有限,只列出部分考点,详细请访问。
分段函数与抽象函数
分段函数:1、分段函数:定义域中各段的x与y的对应法则不同,函数式是分两段或几段给出的; 分段函数是一个函数,定义域、值域都是各段的并集。&抽象函数:
我们把没有给出具体解析式的函数称为抽象函数; 一般形式为y=f(x),或许还附有定义域、值域等,如:y=f(x),(x>0,y>0)。 知识点拨:
1、绝对值函数去掉绝对符号后就是分段函数。 2、分段函数中的问题一般是求解析式、反函数、值域或最值,讨论奇偶性单调性等。 3、分段函数的处理方法:分段函数分段研究。
发现相似题
与“作出函数f(x)=|x-2|-|x+1|的图象,并由图象求f(x)的值域.-高一数..”考查相似的试题有:
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