mathematica 8.0.1小疑问之depth of object

来源：蜘蛛抓取(WebSpider) 时间：2012-05-27 01:19 标签： mathematica 对数
Mathematica的一个小问题,谁能帮我看下a={{1,2,3},{4,5,6}},b={{7,8,9},{10,11,12}}我想让他们一一配对成{1,7},{2,8},{3,9},{4,10},{5,11},{6,12}程序该如何编制呢?这个太容易了，换一个c = {{{1,2},{3,4}},{{7,8},{9,10}}};d = {{5,6},{10,11}};组织成{{1,2,5}，{3,4,6}，{7,8,10}，{9,10,11}}如何编制程序
mbkbuuhsiy
MapThread[Append,{c,d},2]
不对，得出的结果不是我要的，我自己弄得太糟糕了 Flatten[Thread /@ Thread[List[c, d]]]~Partition~3
In[4]:= c = {{{1, 2}, {3, 4}}, {{7, 8}, {9, 10}}};
d = {{5, 6}, {10, 11}};
Flatten[MapThread[Append, {c, d}, 2], 1]
Out[6]= {{1, 2, 5}, {3, 4, 6}, {7, 8, 10}, {9, 10, 11}}
Flatten一层就行了啊。。。
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请教一个mathematica的问题
想在mathematica中定义一个函数f，并且f是x1，x2，x3这三个函数的函数。f，x1，x2，x3全都是与r相关的。函数如下，
f=x1+x2+x3
但是问题就是，目前却不知道x1，x2，x3的具体表达式，只知道x1，x2，x3与r相关。
为了能让mathematica识别f这个函数是与r相关，且还要让mathematica知道x1，x2，x3这三个函数也是与r相关（但是目前不知道具体表达式）。
f函数该怎么写？这个问题该怎么解决呢？
x1，x2，x3 对r的导数不知道为不为0.
这个该怎么解决呢？:rol::rol:
D求导，这个我知道。
但貌似对我的解题没有多大帮助;);)
哦哦，我明白你的意思了。
他们是可导函数。
谢谢啦~~~:victory:
大阪主我明白你意思了。
我明白你的意思了，刚脑袋短路了:rol:
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w1 = Table[w11[[n]] eperp[[n, 1]] + w12[[n]] eperp[[n, 2]], {n, 1, 5}];w2 = Table[w21[[n]] eperp[[n, 1]] + w22[[n]] eperp[[n, 2]], {n, 1, 5}];Length[w11[[1]]][out]=2 "Part specification w11[[1]] is longer than depth of object"头两行是我程序里的两行代码，我希望w11是一个以5个标量作为函数的列表，但是运行的时候报错显示为"Part specification w11[[1]] is longer than depth of object"，所以我查了一下w11[[1]]的长度，发现是2请问各位大神为什么会出现这种情况？用什么方法可以改变w11里面元素的默认长度呢？谢谢
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这段代码不给w11赋值怎么跑……要不你把 = 改成 :=？
没给w11赋值的话，Length[w11[[1]]]确实是2，因为它的FullForm是Part[w11, 1]。
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Enable JavaScript to interact with content and submit forms on Wolfram websites.<td class="t_msgfont" id="postmessage_. +&&2. (2.3*10^-10 + 2.12*10^-10
即使是如上式规整的表达式也不会合并，啥原因呢？Simplify指令都用了呀。请大家指点一下,谢谢！
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2. +&&2. (2.3*10^-10 + 2.12*10^-10)象这样的式子都不简化，太不可思议了，Simplify命令都用了呀。
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