李师傅要王师傅生产一批零件件四小时生产了72个照这样的工作效率还需要二点五小只完成

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数学 正、反比例应用题...
工人李师傅生产一批零件,每天工作6小时12天可以完成,照这样的速度,每天工作8小时,多少天可以完成?(用比例解)
第-1小题正确答案及相关解析
解:设x天可以完成任务.6×12=8x
x=9;答:9天可以完成任务.加工一批零件,王师傅独做要4小时完成,李师傅的工作效率比王师傅的高20%,两人合做这一批零件只要几小时就能完成?
杜山诗惠美1450
1÷[+×(1+20%)]=1÷(+×120%),=1÷(+),=1÷,=(小时);答:两人合作需要小时.
为您推荐:
其他类似问题
王师傅独做要4小时完成,即他的工作效率是,李师傅的工作效率比王师傅的高20%,则李师傅的工作效率是王师傅的1+20%,所以李师傅的工作效率是×(1+20%),则两人的效率和是+×(1+20%),所惟两人合作完成需要:1÷[+×(1+20%)]小时.
本题考点:
简单的工程问题;百分数的实际应用.
考点点评:
首先根据分数加法与乘法的意义求出李师傅的工作效率是完成本题的关键.
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