如何飞扑克牌辨认扑克哪里有?

来源：蜘蛛抓取(WebSpider) 时间：2015-09-22 08:24 标签： 扑克牌如何洗牌
Data structure（10）
void checkCardsNumConcatenation(int * pArray, int length)
int max = 0;
int min = 0;
int countZero = 0;
//count for the number of zero
int diff = 0;
if(NULL == pArray || 0 == length)
cout&&&\nno array to check!&&&
if(1 == length || (2 == length && (0 == pArray[0] || 0 == pArray[1])))
cout&&&\nThe & && length&&& numbers are continuity&&&
if(0 == pArray[0])
max = pArray[1];
min = pArray[1];
else if (0 == pArray[0] && 0 == pArray[1])
max = pArray[2];
min = pArray[2];
max = pArray[0];
min = pArray[0];
for(int index = 0; index & index++)
if(0 == pArray[index])
countZero++;
if(pArray[index] & max)
max = pArray[index];
if(pArray[index] & min)
min = pArray[index];
diff = max -
cout&&diff&&
if((0 == countZero && (length -1) == diff) || (1 == countZero && ((length -1) == diff || (length -2) == diff))
|| (2 == countZero && ((length -1) == diff || (length -2) == diff || (length -3) == diff)))
cout&&&\nThe & && length&&& numbers are continuity&&&
cout&&&\nThe & && length&&& numbers are not continuity&&&
int main()
cout&&&\n--------------start of the main()---------------&&&
int sourceNum[] = {0,0,1};
//if the number is zero, it can be every number you needed
checkCardsNumConcatenation(sourceNum, sizeof(sourceNum)/sizeof(sourceNum[0]));
cout&&&\n--------------end of the main()---------------&&&
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creative idea
(2)(1)(1)(5)(3)(12)(24)(3)(1)(4)(1)(2)(10)(2)(1)(1)(3)(7)(14)(2)(2)(13)(17)(24)(28)(43)(17)(24)(1)(1)回形针扑克牌怎样辨认点数
回形针扑克牌怎样辨认点数
10-01-07 &匿名提问
我的自制肥皂纸的方法是：1.把剩余的小香皂切成小碎丁丁后，放进一个小锅里加水，水和香皂丁的比例是1：3即可。2.用大火烧开后再用文火慢慢熬稠，用小勺子舀一勺从高处往锅里倒时，感觉肥皂水很黏。3.把稍厚一点的铜版广告纸裁成扑克牌大小后，在肥皂水里双面浸满，用回形针别在事先拉好的绳上，凉干即可。  把做好后的肥皂纸放入一个小塑料袋里，再放入随身携带的包内，就可随时派上用场了。  不知我的这种方法能否让你也做出自己满意的肥皂纸来。希望你能成功。
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