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/etc/nginx/nginx.conf.我想问一下这是什么软件做的？_百度知道
我想问一下这是什么软件做的？
//c.hiphotos&/zhidao/pic//zhidao/wh%3D600%2C800/sign=fc3d26fbd609b3deebeaec6efc8f40b9/5243fbf2bd7e0238dd3.baidu.baidu://c.jpg" target="_blank" title="点击查看大图" class="ikqb_img_alink"><img class="ikqb_img" src="http.<a href="/zhidao/wh%3D450%2C600/sign=7b2b781c6b10a84051fcc/5243fbf2bd7e0238dd3.jpg" esrc="http.hiphotos://c.baidu
我有更好的答案
玩图 画中画 字中字都能做
我有那个，但是做不起来
可以啊 我都做出来了 点拼图 可以做
亲…………你不要骗我，
又好像是美颜相机
我用过，没有这个
好多种，相应ps较普遍专业些
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出门在外也不愁想问一下怎么用Python编一个 同时投12个骰子 计算每次投出12个骰子后至少出现两个六的次数及概率的程序
每次至少有两个这个地方不知道如何说明 我自己写的感觉太麻烦而且好像也写错了…初学者… 求助
谢邀，用random去模拟随机，应该很简单random使用前要给一个种子(一般用当前时间), 否则每次都是同一个随即序列生成12个随机数用列表生成式列表中找出特定元素(6)的个数可以用 list的count方法以下是示例代码# -*- coding: utf-8 -*-
import random
from datetime import datetime
random.seed(datetime.now())
x, y = 0,0
while True:
if [random.randint(1, 6) for i in range(12)].count(6) &= 2:
print("模拟%d次,概率为%d/%d = %f" % (y, x, y, float(x)/y))
你把它当成概率问题来算简单些，非要模拟的话，，好像挺好玩的样子，晚点更&br&&br&&div class=&highlight&&&pre&&code class=&language-python&&&span class=&c&&#-*-coding=utf-8 -*-&/span&
&span class=&kn&&import&/span& &span class=&nn&&random&/span&
&span class=&c&&#roll--投12次骰子,计算6出现2次以上的概率&/span&
&span class=&k&&def&/span& &span class=&nf&&roll&/span&&span class=&p&&():&/span&
&span class=&n&&i&/span&&span class=&o&&=&/span&&span class=&p&&[&/span&&span class=&n&&random&/span&&span class=&o&&.&/span&&span class=&n&&randint&/span&&span class=&p&&(&/span&&span class=&mi&&1&/span&&span class=&p&&,&/span&&span class=&mi&&6&/span&&span class=&p&&)&/span& &span class=&k&&for&/span& &span class=&n&&i&/span& &span class=&ow&&in&/span& &span class=&nb&&range&/span&&span class=&p&&(&/span&&span class=&mi&&12&/span&&span class=&p&&)]&/span&&span class=&o&&.&/span&&span class=&n&&count&/span&&span class=&p&&(&/span&&span class=&mi&&6&/span&&span class=&p&&)&/span&
&span class=&k&&if&/span& &span class=&n&&i&/span&&span class=&o&&&=&/span&&span class=&mi&&2&/span&&span class=&p&&:&/span&
&span class=&k&&return&/span& &span class=&mi&&1&/span&
&span class=&k&&else&/span&&span class=&p&&:&/span&
&span class=&k&&return&/span& &span class=&mi&&0&/span&
&span class=&c&&#main--进行游戏&/span&
&span class=&k&&def&/span& &span class=&nf&&main&/span&&span class=&p&&(&/span&&span class=&n&&game_num&/span&&span class=&p&&):&/span&
&span class=&n&&P&/span&&span class=&o&&=&/span&&span class=&mf&&0.0&/span&
&span class=&k&&for&/span& &span class=&n&&i&/span& &span class=&ow&&in&/span& &span class=&nb&&xrange&/span&&span class=&p&&(&/span&&span class=&n&&game_num&/span&&span class=&p&&):&/span&
&span class=&n&&p&/span&&span class=&o&&=&/span&&span class=&n&&roll&/span&&span class=&p&&()&/span&
&span class=&n&&P&/span&&span class=&o&&+=&/span&&span class=&n&&p&/span&
&span class=&k&&print&/span& &span class=&s&&u'进行了&/span&&span class=&si&&%d&/span&&span class=&s&&次游戏，投12次骰子，6每次出现2次以上的概率为：&/span&&span class=&si&&%f&/span&&span class=&s&&'&/span&&span class=&o&&%&/span&&span class=&p&&(&/span&&span class=&n&&game_num&/span&&span class=&p&&,&/span&&span class=&n&&P&/span&&span class=&o&&/&/span&&span class=&n&&game_num&/span&&span class=&p&&)&/span&
&/code&&/pre&&/div&&img data-rawwidth=&677& data-rawheight=&442& src=&/36b94b3bd508b3fabd410_b.jpg& class=&origin_image zh-lightbox-thumb& width=&677& data-original=&/36b94b3bd508b3fabd410_r.jpg&&简单写了一个脚本，用for循环，效率较低。&br&(#‵′)靠！！！为什么不能上传照片！！！
你把它当成概率问题来算简单些，非要模拟的话，，好像挺好玩的样子，晚点更#-*-coding=utf-8 -*-
import random
#roll--投12次骰子,计算6出现2次以上的概率
def roll():
i=[random.randint(1,6) for i in range(12)].count(6)
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python程序猿，http://pqx.ee请说明步骤或者程序框图或者编写程序!请按照给的问题回答,我不知道所以问问 请标明回答的是第几题.还有怎么获得问问的积分?我数学不好所以想问问 一个球从100m高处自由落下,每次着地后又跳回去原高度的一半再落下.编写程序,求当它第10次着地时,（1）向下的运动共经过多少米?（2）第10次着地后又反弹多高?（3）全程共经过多少米?编写程序,将用户输入的正整数转换成相应的星期值输出.如果输入3,则输出W用户输入0,则输出Sunday.如果用户输入的数大于6,则用这个数除以7所得的余数进行上述操作.画出程序框图,用二分法球方程1.3X^3-26.013X^2+0.975X-19.50975=0ZAI (20,21)之间的近似根（精确度为0.005）.设计一个算法,判断一个正的n(n>2)位数是不是回文数,用自然语言描述算法步骤.（回文数）：是指从左到右读与从右到左读都是一样的正整数,如121,676,94249等）
清枫yy4j67
第一题 dim h,a,y,i,b h=100 for i =0 to 10 h=h/2 y=a a=2*h+h b=b+h y=y+a next i y=y-h b=b-h+100 print h y (y代表10次落地时运行的总距离,h代表运行10次后可以反弹多高,b代表滴10次落地时向下运动总距离) 第二题太简单了就是运用一个求余函数,这上面不好写程序就不写了.第三题难得画图,也难得看这么长的程式 第四题的其中一种写程序的思路是：1.将数值转换为字符 2.求出字符位数N 3.用FOR循环（n-1）/2次,再将N位数与1位数对比,N-I位与2位对比,在每次得出的真与假进行if判断就行了
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