定义一个matlab tree函数类,包括成员ages。成员函数grow(int years)对ages加上years.

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Circle 类,有
成 员 函 数
grow(int years) 对
请输入年份:5
Radius(半径)
ages 加上 years
该树年龄为:10
GetValue()用来给
age()显示对象的数
3. 声明一个名为
Rectangle 的矩
形类,其属性为矩形的左下角和
GetArea()计算圆的
tree(int n=0)进行初
右上角两点的坐标,并有成员函
数计算矩形的周长及面积。编程
在主函数中创建一个
Circle 类的
在主函数中创建一个
tree 类的对
实现求左下角与右上角坐标分别
对象进行测试,显示出面积。
象进行测试(创建一个树龄为
为(2.1,3.2),(5.2,6.3)的
的对象,调用
age()显示树龄,之
矩形周长及面积。
grow(4),生长
class circle
显示树龄)。
class Rectangle
class tree
void getvalue()
SetPoint(double
l,double b,double r,double t)
double getarea()
void grow(int years);
void age();
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(C)2006 Tsinghua Tongfang Knowledge Network Technology Co., Ltd.(Beijing)(TTKN) All rights reserved定义一个Tree类有成员ages&树龄&
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#includclass circle{ private:public: circle(double r=0.0); void input(); double c(); double s();};circle ::circle (double r)7.定义一个tree类,包括成员ages.成员函数grow(int years)对ages加上years,age()显示
7.定义一个tree类,包括成员ages.成员函数grow(int years)对ages加上years,age()显示tree对象的ages的值.
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与《7.定义一个tree类,包括成员ages.成员函数grow(int years)对ages加上years,age()显示》相关的作业问题
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我说下思路吧.画一个矩阵只需要知道左上点和右下点的坐标,故类中需相应的成员变量保存这两点.不知道你说的旋转是以什么点为中心来转,就假定为矩形的中心吧,旋转还要有个旋转角度吧?另外图形的旋转牵涉到矩阵的乘法,这是计算机图形学的内容,你可以百度得到相应的算法,也就是一些几何知识.放大也可以以中心点为基准,按着欲放大的倍数得
class complex{public:complex( int _real,int _img ) { real = _ img = _ }complex & operator + ( complex & x ){real += x.img += x.im
#include#includclass Point{private:double X,Y;public:Point(double x,double y){X=x;Y=y;}//构造函数double GetX(){return X;}double GetY(){return Y
//main函数里能输入两个复数.已经用VC++6.0编译通过了...希望对你有帮助#include#includeclass Complex{private:public: Complex(float r=0.0,float i=0.0) { real=r; im
修改如下,调试无误:#include&&iostream&#include&&cmath&using&namespace&//实现POINT类class&POINT{protected://private:& &
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In a two-dimensional Cartesian coordinate system, creating a point class, the class name is Point, class Line is derived from the class Point and then to implem
把这三个类分别放到三个.java文件中,然后编译运行即可.public class Circle{ public Circle(double r){ this.r = } public double getZhou(){ return 2*Math.PI*r; } public
class cs{public int _w;public int _h;pulic cs( int w,int h ){_w=w;_h=h;}public int mj(){return _w*_h;}public int zc(){retrun (_w+_h_)*2;}}手写的!

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