4x^2-4x-y^2+4y-3

来源：蜘蛛抓取(WebSpider) 时间：2011-08-21 09:21 标签： 4x 4y
已知2x^2+4x+y^2=2xy-4,求x^y的值_百度作业帮
已知2x^2+4x+y^2=2xy-4,求x^y的值
已知2x^2+4x+y^2=2xy-4,求x^y的值
已知2x^2+4x+y^2=2xy-4,求x^y的值x²+4x+4+x²-2xy+y²=0;(x+2)²+(x-y)²=0;x+2=0;x=-2;x-y=0;y=x=-2;∴x^y=(-2)^(-2)=1/4;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,
2x^2+4x+y^2=2xy-4∴(x²+4x+4)+(x²-2xy+y²)=0∴(x+2)²+(x-y)²=0∵(x+2)²≥0,(x-y)²≥0∴x=-2,x=y∴x=y=-2x^y=(-2)^(-2)=1/(-2)²=1/4 明教为...
原方程式可以写为：x^2+4x+4+x^2+y^2-2xy=0,
即(x+2)^2+(x-y)^2=0,所以 x = -2, y = x =-2, x^y = 1/4.若4x^2+8xy+4y^2+4y-3=0,求x+y的值_百度作业帮
若4x^2+8xy+4y^2+4y-3=0,求x+y的值
若4x^2+8xy+4y^2+4y-3=0,求x+y的值
4x^2+8xy+4y^2+4x+4y-3=4(x+y)^2+4(x+y)-3=[2(x+y)-1][2(x+y)+3]=02(x+y)-1=0或2(x+y)+3=0x+y=1/2或x+y=-3/2
4x^2+8xy+4y^2+4y-3=0----->4(x^2+2xy+y^2)+4y-3=0------>4(x+y)^2+4y-3=0----->(x+y)^2=3/4-y---->只要能保证3/4-y≥0即可------>y≤3/4即可。随便找个符合此条件的y，3/4-y范围可以是全体正数，而x+y只需要将这个数开方一次即可，所以x+y可以是任意正数。因式分解4x^2-4x(y-1)(y-1)^2_百度作业帮
因式分解4x^2-4x(y-1)(y-1)^2
因式分解4x^2-4x(y-1)(y-1)^2
4x^2-4x(y-1)(y-1)^2=4x[x-(y-1)(y-1)^2]=4x[x-(y-1)^3]分解因式1).4x^2-4x-y^2+4y-32).(x+y-2xy)(x+y-2)+(xy-1)^23).4x^3-31x+154).x^3+5x^2+3x-95).(x^4-4x^2+1)(x^4+3x^2+1)+10x^4一步一步过程写出来_百度作业帮
分解因式1).4x^2-4x-y^2+4y-32).(x+y-2xy)(x+y-2)+(xy-1)^23).4x^3-31x+154).x^3+5x^2+3x-95).(x^4-4x^2+1)(x^4+3x^2+1)+10x^4一步一步过程写出来
1).4x^2-4x-y^2+4y-32).(x+y-2xy)(x+y-2)+(xy-1)^23).4x^3-31x+154).x^3+5x^2+3x-95).(x^4-4x^2+1)(x^4+3x^2+1)+10x^4一步一步过程写出来
1、原式=(4x^2-4x+1)-(y^2-4y+4) =(2x-1)^2-(y-2)^2 =(2x-1+y-2)(2x-1-y+2) =(2x+y-3）(2x-y+1) 2、原式=(x+y)^2-2xy(x+y)-2(x+y)+4xy+(x^2y^2-2xy+1) =(x+y)^2+2(xy+1)(x+y)+(x^2y^2+2xy+1) =(x+y)^2+2(xy+1)(x+y)+(xy+1)^2 =(x+y+xy+1)^2 3、原式=4x^3-2x^2+2x^2-31x+15 =2x^2(2x-1)+(2x-1)(x-15) =(2x-1)(2x^2+x-15) =(2x-1)(2x-5)(x+3) 4、原式=x^3+4x^2+3x+x^2-9=x(x^2+4x+3)+(x+3)(x-3)=x(x+1)(x+3)+(x+3)(x-3)=(x+3)(x^2+2x-3)=(x+3)^2(x-1)5、原式=(x^4+1)^2-x^2(x^4+1)-12x^4+10x^4=(x^4+1)^2-x^2(x^4+1)-2x^4=(x^4+1-2x^2)(x^4+1+x^2)=(x^2-1)^2·(x^2+1)^2=(x+1)^2(x-1)^2·(x^2+1)^2
您可能关注的推广X^2+4X+Y^2-2Y+5=0 则X+Y等于什么?_百度作业帮
X^2+4X+Y^2-2Y+5=0 则X+Y等于什么?
X^2+4X+Y^2-2Y+5=0 则X+Y等于什么?
X^2+4X+Y^2-2Y+5=(X+2)^2+(Y-1)^2=0∴(X+2)^2=0,(Y-1)^2=0∴X=-2,Y=1X+Y=-1

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