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时间:2011-10-12 12:37
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pv1 f 1x4
1/1x4+1/4x7+1/7x10+1/10x13+1/13x16+1/16x19+1/19x22找规律谢谢。
1/(3n-2)(3n+1)=1/3{1/(3n-2)-1/(3n+1)}所以答案为1/3*(1-1/22)==7/22
1/n*(n+3)+1/(n+3)*(n+2*3)。。。。。。第N个就是1/【n+(n-1)*3】*(n+3n)注:*为乘号【】为中括号
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