请问c语言程序运行错误为何报错啊，C++

来源：蜘蛛抓取(WebSpider) 时间：2015-10-09 01:23 标签： vrvrf c.exe程序错误
C++报错尝试引用已删除的函数有图 有代码，为何，求速度，谢谢。。。
来源：csdn
【VS2015双击错误得到的提示位置在这
friend istream operator>>(istream &in, Student &s)
in >> s.m_ID >> s.m_Name >> s.m_Sex >> s.m_Tel >> s.m_E
friend ostream operator<<(ostream &out, const Student &s)
out<< s.m_ID << s.m_Name << s.m_Sex << s.m_Tel << s.m_E
全部代码（还未完成）在此，大神们顺便看看这个入门的单向链表的使用是否正确
#pragma once
static int number = 0;
class Student
protected:
string m_N
string m_S
string m_T
Student(int ID = 0, string Name = "δ?", string Sex = "δ?", string Tel = "δ?", int English = 0)
m_ID = ID;
m_Name = N
m_English = E
Student(const Student &s)
m_ID = s.m_ID;
m_Name = s.m_N
m_Sex = s.m_S
m_Tel = s.m_T
m_English = s.m_E
~Student()
friend istream operator>>(istream &in, Student &s)
in >> s.m_ID >> s.m_Name >> s.m_Sex >> s.m_Tel >> s.m_E
friend ostream operator<<(ostream &out, const Student &s)
out << s.m_ID << s.m_Name << s.m_Sex << s.m_Tel <>(istream &in, Graduate &s)
in >> s.m_ID >> s.m_Name >> s.m_Sex >> s.m_Tel >> s.m_English >> s.m_Majorfield >> s.m_P
friend ostream operator<<(ostream &out, Graduate &s)
out<< s.m_ID <<endl
<<s.m_Name <<endl
<<s.m_Sex <<endl
<<s.m_Tel <<endl
<<s.m_English <<endl
<<s.m_Majorfield <<endl
<<s.m_Papers<>(istream &in, Undergraduate &s)
in>> s.m_ID >> s.m_Name >> s.m_Sex >> s.m_Tel >> s.m_English >> s.m_Math >> s.m_C
friend ostream operator<<(ostream &out, Undergraduate &s)
out<<s.m_ID <<endl
<<s.m_Name <<endl
<<s.m_Sex <<endl
<<s.m_Tel <<endl
<<s.m_English <<endl
<<s.m_Math <<endl
<<s.m_Cpp<<
#pragma once
#include"student.h"
class LinkL
class Node
data = &t;
next = NULL;
next =NULL
next = NULL;
T SetData(T &t)
data = &t;
void ShowData()
cout << data<<
friend LinkL
class LinkList
protected:
LinkList()
this->m_head = NULL;
void InsertAtHead(const Node &t)
p = new Node(t);
p->next = m_
void show()
while (p != NULL)
p->ShowData();
#include"链表.h"
#include"graduate.h"
#include"undergraduate.h"
void main()
LinkList list1;
list1.InsertAtHead(Student(5,"xiaosan","man","",98));
list1.show();
friend istream operator>>(istream &in, Student &s)改成friend istream& operator>>(istream &in, Student &s)返回引用试试
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