Java标准为什么不加入unsignedjava int类型最大值

来源：蜘蛛抓取(WebSpider) 时间：2016-05-03 06:08 标签： java int类型范围
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blogTitle:'java中无符号类型的处理[转]',
blogAbstract:'在Java中，不存在Unsigned无符号数据类型，但可以轻而易举的完成Unsigned转换。 方案一：如果在Java中进行流(Stream)数据处理，可以用DataInputStream类对Stream中的数据以Unsigned读取。 Java在这方面提供了支持，可以用java.io.DataInputStream类对象来完成对流内数据的Unsigned读取，该类提供了如下方法： （1）int&& readUnsignedByte()&&& //从流中读取一个0~255(0xFF)的单字节数据，并以int数据类型的数据返回。返回的数据相当于C/C++语言中所谓的“BYTE”。 （2）int readUnsignedShort()&&
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{list wl as x}{/list}Convert int to unsigned short java - Stack Overflow
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I have written a .obj parser in java to modelize 3D objects on iPhone. I would like to export the data as a binary file, which must be as small as possible. I have plenty of indices that would fit a unsigned short, but they are represented as int in java.
I would like to use the ByteBuffer class to do the conversion just before writing the data in a file. I suppose I will have to manipulate bytes before pushing them into the ByteBuffer but I have no idea how to do so.
Thank you in advance if you can help me.
In Java, an unsigned short can be represented as a char. Just cast the int to char and use putChar() on the ByteBuffer.
myBuffer.putChar((char) my16BitInt);
117k30229261
short toUint16(int i)
return (short)
int toUint32(short s)
return i & 0xFFFF;
41.1k28134228
You can extract single bytes from your integers with
byte b1 = i & 0xFF;
byte b2 = (i && 8) & 0xFF;
dos.writeShort(value & 0xFFFF);
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