4≤12t≤6怎么化简1cos2xcos4xcos6x

化简:(√6+4√3+3√2)/[(√6+√3)(√3+√2)]
韻酭儩酼006F3
(√6+4√3+3√2)/[(√6+√3)(√3+√2)]= (√6+√3+3√3+3√2)/[(√6+√3)(√3+√2)]=1/(√3+√2)+3/(√6+√3)=√3-√2+(√6-√3)=√6-√2(做这样的题要先观察题的特点,想方法把分母约分掉一部分,然后分母有理化,最后化简求值)
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(√6+4√3+3√2)/[(√6+√3)(√3+√2)]= (√6+√3+3√3+3√2)/[(√6+√3)(√3+√2)]=1/(√3+√2)+3/(√6+√3)=√3-√2+(√6-√3)=√6-√2(做这样的题要先观察题的特点,想方法把分母约分掉一部分,然后分母有理化,最后化简求值)赞同6
扫描下载二维码分解因式 -4(x+y)²+16(x-y)² (p-4)(p+1)+3p 化简求值 (9-12t+4t²)÷(3-2t)其中t=3分解因式 -4(x+y)²+16(x-y)² (p-4)(p+1)+3p 化简求值 (9-12t+4t²)÷(3-2t)其中t=3八点之前要发来,
(1)-4(x+y)^2+16(x-y)^2=4[(2x-2y)^2-(x+y)^2]=4[(2x-2y)+(x+y)][(2x-2y)-(x+y)]=4(3x-y)(x-3y)(2)(p-4)(p+1)+3p =p^2-3p-4+3p=p^2-4=(p+2)(p-2)(3) (9-12t+4t²)÷(3-2t)=(3-2t)^2/(3-2t)=3-2t=3-2*3=-3
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-4(x+y)2+16(x-y)2 =4[4(x-y)2-(x+y)2]=4[(2x-2y+x+y)(2x-2y-x-y)]=4(3x-y)(x-3y)(p-4)(p+1)+3p =p2-3p-4+3p=p2-4=(p+2)(p-2)(9-12t+4t2)÷(3-2t)=(3-2t)2÷(3-2t)=3-2t 当t=3时,原式=-3
-4(x+y)²+16(x-y)² =-4(x2+2xy+y2)+16(x2-2xy+y2)=12x2-40xy+12y2(p-4)(p+1)+3p =p2-4p+p-4+3p=p2-4(9-12t+4t²)÷(3-2t)=(2t-3)(2t-3)/(-(2t-3))=3-2t=3-6=-3
扫描下载二维码化简比.5/6:4/9
5/6*18:4/9*18=15:8
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两边同乘以18得15:8
=15/18:8/18=15:8
5/6;4/9=5/6*(9/4)15/8
扫描下载二维码(9-t)×(6+2t)和(9-t)×(6﹣2t)分别怎么化简
面皮呱呱Nx
(1)-2t-12t+54(2)-2t-24t+54
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