来源:蜘蛛抓取(WebSpider)
时间:2011-10-25 09:56
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跪求好看的电视剧
Z=u2v-uv2,u=xcosy,v=xsiny,求αz/αx和αz/αy(微分)Z=u^2• v-u• v^2,u=xcosy,v=xsiny,求αz/αx(注:式中2为指数)求αz/αx和αz/αy
z=x³cos²ysiny-x³cosysin²y=x³sinycosy(siny+cosy)∂z/∂x,则把y看成常数所以∂z/∂x=2x²sinycosy(siny+cosy)∂z/∂y,把x看成常数∂z/∂y=x³*[(siny)'cosy(siny+cosy)+siny(cosy)'(siny+cosy)+sinycosy(siny+cosy)']=x³[cos²y(siny+cosy)-sin²y(siny+cosy)+sinycosy(cosy-siny)]=x³[(cos²y-sin²y)(siny+cosy)+sinycosy(cosy-siny)]=x³(cosy-siny)[(siny+cosy)²+sinycosy]=x³(cosy-siny)(1+3sinycosy)
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其他类似问题
dz/dx=(2u*u')+u^2*v'-u'* v^2-2uv*v'
v'=sinydz/dy=(2u*u')+u^2*v'-u'* v^2-2uv*v'
u'=-xsiny v'=xcosy希望你看得懂,我就简单写一下,实际写的时候u' v'要写成对应x、y的导数形式
dz/dx=(2u*u')+u^2*v'-u'* v^2-2uv*v'
v'=sinydz/dy=(2u*u')+u^2*v'-u'* v^2-2uv*v'
u'=-xsiny v'=xcosyz=x³cos²ysiny-x³cosysin²y=x³sinycosy(siny+cosy)...
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