等比数列等比中项前102项和是10,前202项和是30,则它的前30项和是多少

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等差数列{an}的前n项和为Sn,数列{bn }是等比数列,满足a1为3,b1为1,b2+S2为1等差数列{an}的前n项和为Sn,数列{bn}是等比数列,满足a1为3,b1为1,b2+S2为10,a5-2b2=a3。求数列{an}和{bn}的通项公式谢谢 最好有过程 我是真不会才会在这里问大家的啦
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等比数列的前10项之和为10,前20项之和是30,则前30项之和是?
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等比数列前n项和的性质:依次每k项的和成等比数列。依题意:S10=10,S20-S10=30-10=20(S20-S10)/(S10)=(S30-S20)/(S20-S10)20/10=(S30-S20)/20S30-S20=40S30=S20+40=30+40=70.
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人教版必修一匀变速直线运动的研究综合测试题(带解析)(分值:100分 时间:60分钟)一、选择题(本大题共7个小题,每小题6分,共计42分,在每小题给出的四个选项中,有的只有一项符合题目要求,有的有多项符合题目要求.全部选对的得6分,选对但不全的得3分,有选错的得0分)1.(;锦州期中)甲物体的重力是乙物体重力的5倍,两者在同一地方,甲从高H处、乙从高2H处同时自由下落,未落地之前以下几种说法正确的是(  )A.两物体下落过程中,同一时刻甲的速度比乙的大B.下落1 s时,它们的速度相等C.在各自下落1 m时,它们的速度相等D.下落过程中甲的加速度比乙的大【解析】 物体在下落过程中做自由落体运动,加速度为重力加速度g,与质量无关,选项D错误;根据v=gt可知,选项A错误,B正确;由v2=2gh可知选项C正确.【答案】 BC&图12.(;厦门一中高一检测)如图1所示,桌面离地面的高度是0.8 m,坐标系原点定在桌面上,向上方向为坐标轴的正方向,从桌边与桌面相平处的A点自由释放一个小球,经过一段时间落到地面,设小球下落的加速度大小是10 m/s2,则从释放到落地,小球的(  )A.位移是0.8 mB.位移是-0.8 mC.运动时间是0.2 sD.落地速度是-4 m/s【解析】 由于向上为位移正向,故从释放到落地位移是-0.8 m,A错B对,由v2=2gh得,v=2gh=4 m/s.考虑方向后,落地速度应为-4 m/s,D对,又t=vg=0.4 s,C错.【答案】 BD3.(;泰安一中高一期末)自由落体第5个0.5 s经过的位移是第1个0.5 s经过的位移的倍数为(  )A.5   &B.9    C.10    &D.25【解析】 第1个0.5 s内位移h1=12gt21=12×10×0.52 m=1.25 m.第5个0.5 s内位移h2=12gt22-12gt23=12×10×2.52 m-12×10×22 m=11.25 mn=h2h1=11.251.25=9.【答案】 B4.(;江门一中高一期末)一小球从O点开始做自由落体运动,若到达A点时速度为v,到达B点时速度为2v,则OA∶AB等于(  )A.1∶1& &B.1∶2& C.1∶3& &D.1∶4【解析】 由公式v2=2ax得v2=2g•OA (2v)2=2g•OB故OA∶OB=1∶4所以OA∶AB=1∶3,C对.【答案】 C&图25.(;汕头一中高一检测)如图2所示为甲、乙两物体沿同一直线运动的x-t图象,下列说法中正确的是(  )A.两物体的初速度都为零B.甲、乙两物体相遇时,速度大小相等C.在t1时间内两物体的平均速度大小相等D.甲物体做变加速直线运动,乙物体做匀加速直线运动【解析】 两物体从x=0处计时,而此时两图象的斜率不为零.即初速度不为零,A错,两物体相遇时,两图象不平行,速度不相等,B错,由于同时同地出发,故相遇时,位移、时间相同,由v=xt知,两物体在t1时间内平均速度相同,C对,由乙图知,乙物体做匀速直线运动,D错.【答案】 C&图36.(;贵阳一中高一检测)如图3是某物体做直线运动的v-t图象,由图象可得(  )A.t=1 s时物体的加速度大小为1.0 m/s2B.t=5 s时物体的加速度大小为0.75 m/s2C.第3 s内物体的位移为1.5 mD.物体在加速过程的位移比减速过程的位移大【解析】 t=1 s时物体的加速度a1=32 m/s2=1.5 m/s2,A错.t=5 s时物体的加速度a2=0-37-3 m/s2=-0.75 m/s2,B对.第3 s内物体的位移x=3×1 m=3 m,C错.物体在加速过程的位移x1=12×3×2 m=3 m,减速过程的位移x2=12×3×4 m=6 m,D错.【答案】 B7.汽车正在以10 m/s的速度在平直的公路上前进,在它的正前方x处有一辆自行车以4 m/s的速度做同方向的运动,汽车立即关闭油门做a=-6 m/s2的匀变速运动,若汽车恰好碰不到自行车,则x的大小为(  )A.9.67 m& &B.3.33 mC.3 m& &D.7 m【解析】 若恰好碰不到,则汽车和自行车速度相等时,恰好追及,即x汽=x+x自,x汽=v21-v22-2a,x自=v2t,v2=v1+at,由以上各式代入数据解得x=3 m.【答案】 C二、非选择题(本大题共5个小题,共58分.计算题要有必要的文字说明和解题步骤、有数值计算的要注明单位)8.(6分)(;重庆一中高一期末)用接在50 Hz交流电源上的打点计时器测定小车做匀加速直线运动的加速度,得到如图4所示的一条纸带,从比较清晰的点开始起,取若干个计数点,分别标上0、1、2、3…(每相邻的两个计数点间有4个打印点未标出),量得0与1两点间的距离x1=30 mm,3与4两点间的距离x4=48 mm,则小车的加速度为________ m/s2,2与3两点间的距离约为________ mm,打计数点3时的瞬时速度为________ m/s.&图4【解析】 根据Δx=aT2 则x4-x1=3aT2a=48×10-3-30×10-33×0.12 m/s2=0.6 m/s2x3-x1=2aT2 所以x3=30 mm+2×0.6×0.12×1000 mm=42 mm.v3=x3+x42T=42×10-3+48×10-32×0.1 m/s=0.45 m/s.【答案】 0.6 42 0.459.(12分)(;海口一中高一检测)汽车刹车前的速度为10 m/s,刹车获得的加速度大小为2 m/s2,则求(1)从开始刹车后8 s内滑行的距离x1;(2)从开始刹车到汽车位移为21 m时所经历的时间t;(3)静止前2.5 s内汽车滑行的距离x2.【解析】 选汽车初速方向为正方向,则a=-2 m/s2刹车时间:t1=(0-v)/a=(0-10 m/s)/-2 m/s2=5 s,则:(1)8 s内刹车位移:x1=(0-v20)/2a=25 m.(2)前21 m内:x=v0t+(12at2)=21 m解得:t=3 s.(3)静止前2.5 s的逆过程:x2=at22=&#.522 m=6.25 m,即:静止前2.5 s内的位移大小为6.25 m.【答案】 (1)25 m (2)3 s (3)6.25 m&图410.(12分)(;烟台高一检测)如图4所示,小球在光滑斜面上做匀减速直线运动,途中依次经过A、B、C三点,且经过两段的时间间隔分别为tAB=1 s,tBC=3 s,且AB=4 m,BC=6 m.求:(1)小球的加速度;(2)小球从A点出发经多长时间返回A点?【解析】 (1)小球在AB段中间时刻瞬时速度v1=ABtAB=41 m=4 m/s小球在BC段中间时刻的瞬时速度v2=BCtBC=63 m=2 m/s小球加速度a=v2-v1t=2-42 m/s2=-1 m/s2.(2)小球在A点vA=v1-at1=4 m/s+1 m/s2×0.5 s=4.5 m/s,由对称性知小球回到A点时速度为vt=-4.5 m/s小球回到A点时间t总=vt-vAa=-4.5-4.5-1 s=9 s.【答案】 (1)-2 m/s2 (2)9 s11.(14分)一辆长途客车正在以v0=20 m/s的速度匀速行驶.突然,司机看见车的正前方x=33 m处有一只狗,如图5甲所示,司机立即采取制动措施.若从司机看见狗开始计时(t=0),长途客车的“速度一时间”图象如图乙所示.&    &&&&&&&&&& 甲          乙图5(1)求长途客车从司机发现狗至客车停止运动的这段时间内前进的距离;(2)求长途客车制动时的加速度;(3)若狗以v=4 m/s的速度与长途客车同向奔跑,狗会不会被撞?【解析】 (1)x=v0t1+12v0(t2-t1)=12v0(t1+t2)=12×20×(0.5+4.5)m=50 m(2)由图象得:a=ΔvΔt=0-204.5-0.5 m/s2=-5 m/s2(3)t=Δv′a=4-20-5 s=3.2 s客车位移为x1=v0t1+v2-v202a=20×0.5+16-4002×-5=48.4 (m)而狗通过的位移为x2=v(t1+t)=4×(0.5+3.2)=14.8 (m)x2+33 m=47.8 m因为x1&x2+33,所以狗将被撞.【答案】 见解析12.(14分)(;新课标全国高考)甲、乙两辆汽车都从静止出发做加速直线运动,加速度方向一直不变.在第一段时间间隔内,两辆汽车的加速度大小不变,汽车乙的加速度大小是甲的两倍;在接下来的相同时间间隔内,汽车甲的加速度大小增加为原来的两倍,汽车乙的加速度大小减小为原来的一半.求甲、乙两车各自在这两段时间间隔内走过的总路程之比.【解析】 设汽车甲在第一段时间间隔末(时间t0)的速度为v,第一段时间间隔内行驶的路程为s1,加速度为a;在第二段时间间隔内行驶的路程为s2.由运动学公式得v=at0&&①s1=12at20&&②s2=vt0+12(2a)t20&&③设汽车乙在时刻t0的速度为v′,在第一、二段时间间隔内行驶的路程分别为s′1、s′2.同样有v′=(2a)t0&&④s′1=12(2a)t20&&⑤s′2=v′t0+12at20&&⑥设甲、乙两车行驶的总路程分别为s、s′,则有s=s1+s2&&⑦s′=s′1+s′2&&⑧联立以上各式解得,甲、乙两车各自行驶的总路程之比为ss′=57.【答案】 5∶7&
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to book tickets& &C. a confirmation letter will be given to us by e-mail& &D. we should tell clerks our own detailed address39. What is the text mainly about?& &A. How to book acrobatic show tickets.& &B. People in Beijing like acrobatic shows.& &C. The introduction of Chinese acrobatic shows.&D. An advertisement for Beijing Acrobatic Show.&&&&&&&&&&&&&&&&&&&&&&&&&&&&& BMy friend Jessie and I have known each other since we were very young. Friendships get more precious as we get older, and when we reached our forties, we decided we needed to put in a little more work to keep our friendship strong, healthy and growing. We pick out one Saturday a month and promise to do something together. Sometimes we have a long lunch out. Other times we go to see a movie or shopping. But at least once a quarter, we have an adventure. In some adventures we drove to our favorite places. In other adventures we spent a night in a place sharing a festival like Christmas or sometimes we just drove, stopping wherever we wanted. We have headed out of the state to Tennessee. We have tried out new restaurants and new shops. xKb& 1.Com&&& One of our adventures took us to a very small town in south Georgia. It was one of those watermelon or cotton or peanut festivals, and we enjoyed buying the handmade gifts and eating the terrific foods. The most impressive was a parade, with local school marching bands and service groups. We joined the parade and began smiling and waving! Everyone smiled and waved back! Of course, their smiling faces turned confused and puzzled as we passed in our car. “Who are these women?” they must have wondered. Finally, we turned a corner and a serious-looking policeman directed us back to the highway. We really had a great day! Fun is always on the menu, whether it’s a weekend trip or a couple of hours over lunch. We talk and have influence on each other’s life. We share our struggles and our happiness. We ask for and receive advice. And we laugh! Don’t keep promising yourself that “someday soon” you will get together with them. Do it now. Pick up your phone and make a plan for this weekend. You need it. Your friend needs it. You’ll be a happier, healthier person for it! 40. Which of the following activities is NOT mentioned in the passage? &A. Driving to favorite places.& &B. Sharing festivals in a place. &C. Going shopping together.&&& &D. Surfing the net together.& 41. What had a strong effect on them when they were in south Georgia? && &A. The Watermelon Festival.&&& &B. The Peanut Festival.& &&C. The handmade gifts.&& &D. The parade.& 42. How does the writer feel when traveling together with her friend?& && &A. Tired.&& &B. Busy.&&&& &C. Confused.&&& &D. Happy. 43. Which of the following is the best title of the passage? &A. An adventure in south Georgia&& &B. Keeping our friendship strong and healthy &C. Having lunch out with a friend&& &D. Getting together once in a quarter& &&&&&&&&&&&&&&&&&&&&&&&&&&&&& CA sudden screaming voice of a lady made everybody within a distance on the road stop and look back at her. It was a frightful moment when we realized why she had screamed. Her child was about to get hit by a car. After the situation came in control, a few of us went to the lady and asked her what happened. We got to know that her child had seen his uncle standing on the other side of the road and out of excitement ran towards him on the busy road.Well, this was just an example of how accidents take place due to children and how the chances of these children meeting with accidents are more than the adults because they are not familiar with the road safety rules. The recent survey on traffic accidents shows that the road accidents happened to children from the age of 10 to 12 has increased whereas there was a decline in the accident ration of the children from the age of 13 and above. One of the important things that both parents and teachers should teach them is the importance of road safety. They should be told about the consequences of what happens when a person does not follow traffic rules. If the children are taught to follow all the traffic rules then the chances of road accidents become less.In most of the schools, road safety rules are taught to the students by showing them pictures. The students should also be taught not to rush while boarding or getting down from the school bus. One of the important steps of road safety rules is not to talk while crossing the road. We think there is no need to learn traffic rules because we all have common sense, but what it seems to be so easy is not that easy actually. There is a long list of such instances where almost one person dies every day in a road accident. With a conscious mind we can easily avoid such accidents and teach children the same for their safety. 44. More children under 12 met with the road accidents probably because    .&& &A. they liked playing in the street&B. they usually broke traffic rules&C. they were too young to walk&D. they were not protected well&& 45. We can learn from Paragraph 3 that    .&& &A. students should be taught to obey the traffic rules&& &B. parents should take responsibility for their children’s accidents&& &C. teachers owe a duty of care to all their students && &D. parents should teach their children how to walk carefully&&&&&&&&&&&&&&&&&&&& 46. Which of the following can help children keep safe on the road?&& &a. Getting off the school bus as soon as possible.&& &b. Talking while walking on the road.&& &c. Crossing the roads at the zebra crossing properly.&& &d. Boarding the school bus in turn & &A. a, c&B. b, c&C. a, b&D. c, d&&&&&&&&&&&&&&&& 47. What’s the best title of the passage?&& &A. Learning traffic rules is important for the children&& &B. More traffic accidents happen on the road every day && &C. Parents and teachers should keep the children healthy&& &D. What seems to be easy is usually not that easy at all&&&& &&&&&&&&&&&&&&&&&&&&&&&&&&&& DA 77-year-old former traffic policeman, who had cared for his Alzheimer’s-stricken wife for ten years, walked into the hospital where she was being treated and shot her three times. Vitangelo Bini then sat down at the foot of her bed to call the police. When they arrived he told them, “I couldn’t stand to see her suffer any more.” Mr Bini, from Prato, in Tuscany, was in custody (监护) last night after being charged with homicide (杀人罪). His wife, Mara Tani, 82, had suffered from an advanced state of Alzheimer’s for about ten years and was admitted to the Misericordia e Dolce hospital in Prato last week when she lost consciousness. Mr Bini, who had been her full-time carer, had visited her several times a day, hospital staff told the police. On Saturday, however, witnesses said that he entered the room that she shared with five other women, hugged her and then put a towel over her face before shooting her in the head. A few seconds later he fired another shot to the head and one to the heart, Fabio Di Chierri, the vice-director of Prato police station, said. Mr Di Chierri said that Mr Bini sat down and tried to call the police on his mobile phone. He could not get through, perhaps because so many others in the neighborhood were doing the same. Police officers happened to be on the same floor and arrived immediately. Mr Bini did not put up any resistance and tried to explain his actions, although he appeared and sounded dazed (恍惚的) and confused, the officers said. The couple’s children, a son, 43, and a daughter, 44, were stunned by the news and did not see their father when they went to the police station.48. The underlined word “stunned” in the last paragraph can be replaced by “   ”.&A. disappointed& &B. shocked&&&&&&&&& &C. excited&&&&&&&& &D. depressed49. We can learn from the passage that    .&A. the couple has three children&&& &&&&B. the couple’s children never looked after their mother&C. Mr Bini was tired of caring for his wife&& &&D. Mara Tani must have suffered a lot50. What’s the correct order of the news?&a. Mr Bini had visited her several times a day.&b. Mr Bini was charged and left in custody.&c. Mr Bini shot his wife to death.&d. Mara Tani was admitted to the Misericordia e Dolce hospital.&e. Mr Bini sat down and tried to call the police&A. d, b, a, c, e&& &B. b, d, c, a, e&&&&&&& &C. d, a, c, e, b&&&&&& &D. c, b, a, d, e51. The passage is written mainly to    .&A. entertain readers&& &B. attract readers& &C. inform readers&& &D. have pity on the old lady&&&&&&&&&&&&&&&&&&&&&&&&&&& EMoving to a new neighborhood, town, state, or even country can be a pretty scary experience. All you know is that things will be different and chances are you won’t know the kids at your new school. Leaving old friends and familiar places behind can be difficult. However, as you begin the moving process, keep in mind that saying goodbye to your old house, school, and friends does not mean that you have to forget them or that your farewell is permanent! If you’re moving to a new state or even a different country and won’t see your friends for a long time, don’t despair. Make sure to ask everyone for their address so you can write them letters. Also, thanks to the Internet, it is very easy to stay in touch through e-mail or instant messaging technologies. With your parent’s permission, you can even create a blog or web page to record all of your new experiences. Your old friends will love seeing what you are busy with.& Many schools have an orientation program where a local student shows a new students around for their first week. This can help you find your way around the school and make new friends faster. While moving is tough on kids of any age, high school counselor Karen Turner says moves can be particularly difficult for teens. “I think moving during adolescents is an extremely stressful experience, especially if you’re into your early junior high or early senior high year. Students tend to have established a very strong peer network during that period in their lives. Often this has more influence on them even than their families in some cases, and when they’re torn from that there’s often resentment (怨气).” However, Turner adds that while moving isn’t easy, there are things that your parents and the school can do to help you cope with the change. 52. Which of the following is mainly suggested in Paragraph 2?&A. Staying in contact with old friends.&B. Expressing yourself when it’s possible.&C. Forming good habits at school.&D. Keeping positive about your new school.53. According to the passage, an orientation program    .&A. helps local students in many ways &B. is organized by new students&C. offers help to new students&D. focuses on all the students at school54. According to the passage, Karen Turner may agree that    .&A. many parents seem to care little about their children&B. teens can easily be attached to their friends&C. parents should communicate with the school teachers&D. teens tend to behave rudely in a new school55. If this passage continues, what would the author further discuss?&A. What a new school is like.&B. Why parents move with their children. &C. How parents and the school can help the children.&D. How children can express their anxieties.第三部分 书面表达(共两节,满分35分)第一节 阅读表达(共5小题;每小题2分,满分10分) 阅读下面的短文,并根据短文后的要求答题(请注意问题后的词数要求)。It’s important to set a good example for your child by demonstrating healthy ways to react to stressful situations. As difficult as it may be, it’s a good idea to resist the urge to yell when you are disciplining your child. Instead, try to be firm and matter-of-fact. If your child is losing his or her temper, instead of losing yours, too, calmly let your child know that yelling, throwing a tantrum (脾气发作), and slamming doors are unacceptable behavior, and they have consequences. Calmly explain  &&&&&&   .If your child has an occasional temper tantrum or outburst, in many cases, it’s a good idea to show your child that a tantrum is not an effective method to get what he or she wants. For example, if your child gets upset at the grocery store after you’ve explained why you are not buying any candy, if you don’t give in to it, you have demonstrated that a tantrum is unacceptable behavior, and it doesn’t work.If your child frequently loses control and is continually argumentative, or impulsive (易冲动的), or if tantrums last for more than 10 minutes on a regular basis, you may want to talk to your child’s doctor. For school-age children, you may want to also talk to the doctor if the tantrums are accompanied by the following behavior:★ restlessness ★ impulsiveness ★ defiance (挑衅)★ difficulty in concentrating ★ low self-esteem ★ declining performance in school You might also consider talking to your child’s teachers about classroom settings and appropriate behavioral expectations for your child. Look at your own actions to see if you are managing stressful situations as well as you can. If not, you might want to ask your family doctor about whether family counseling sessions may help. 56. What is the best title of the passage? (no more than 10 words)&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& 57. What should you do if your child gets upset at the grocery store because of no candy? (no more than 18 words)&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& 58. Please fill in the blank in Paragraph 1 with proper words. (no more than 5 words)&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& 59. Whom should you turn to if your child frequently loses control? (no more than 5 words)&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& 60. What does the underlined word “they” (Line 7, Paragraph 1) probably refer to? (no more than 8 words)&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& 第二节 书面表达(满分25分)假设上周五,来自安徽医科大学的李教授针对“青少年意外伤害自救能力的现状与建议”做了一次两个小时的报告。请根据以下提示内容,写一篇短文:1. 意外伤害的发生呈逐年上升的趋势。在中国,每年约有20万少年儿童死于意外伤害。意外伤害已经成为青少年健康的“第一杀手”;2. 青少年对急救知识缺乏了解;3. 建议加强青少年对意外伤害急救的教育。注意:1. 词数100左右;2. 可适当增加细节,以使行文连贯。3. 参考词汇:意外伤害accidental injury;自救self rescue 参考答案:1-15 BDCAC&& &DABAD&&&& BCDAC&&& &16-35 BACDC&& &ABCBB&&&& BCACA&& &DBACD36-55 DBCDD &DDBBA&&&& DABDC&&&& CACBC阅读表达56. What to do when your child is out of control57. Explain to your child why you don’t buy them candy and don’t give in to it.58. what those consequences are59. Your child's doctor.60. Yelling, throwing a tantrum and slamming doors.One possible version:Last Friday, Professor Li from Anhui Medical University gave us a report on teenagers’ accidental injury and self rescue. The report lasted two hours.Professor Li said that the rate of accidental injury is increasing year by year. In China, about 200,000 children die of accidental injury each year. Accidental injury has become the leading cause of death for teenagers. However, most teenagers lack the basic knowledge of first aid. At the end of the report, Professor Li called on us to realize the importance of gaining the first aid knowledge. He said that it was high time that we teenagers received education on first aid.&
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高一必修一营造地表形态的力量巩固测试题(带答案人教版)&1.下列地质作用中属于内力作用表现形式的是(  )①2010年5月冰岛火山喷发 ②喜马拉雅山脉的隆起 ③黄果树瀑布形成 ④黄土高原的形成A.①②&&&& B.②③C.①④&&&& D.①②③④答案:A下图为四种地貌景观图,读图完成2~3题。&解析:本题组主要考查内外力作用形成的各种地貌及其分布,由图可知:①为喀斯特地下地貌,由流水溶蚀作用形成。②为内力作用下形成的裂谷。③为风蚀蘑菇。④为火山喷发。2.上述四种地貌景观形成过程中,能量主要来自地球内部的是(  )A.①②&&&& B.③④&&&& C.①③&&&& D.②④解析:裂谷和火山喷发的能量来自地球内部。答案:D3.上述四种地貌景观的形成与岩石的性质、干燥多风的气候条件密切相关的是(  )A.①&&&& B.②&&&& C.③&&&& D.④解析:风蚀蘑菇是在气候干旱、多大风的条件下形成的,风速越大,侵蚀力越强,也可能是岩层上硬下软,下部容易遭受侵蚀的条件下形成的。答案:C4.关于地壳物质循环运动的正确叙述是(  )①岩浆→岩石→新岩浆是地壳物质的基本循环运动过程 ②只有沉积岩能够变成变质岩 ③沉积物只来源于岩浆岩和变质岩 ④参与地壳物质循环的地质作用既有内力作用,又有外力作用A.①②&&&& B.②③&&&& C.①④&&&& D.③④解析:三种岩石均可能受外力作用形成沉积物,也均可变成变质岩。答案:C5. (;江门一模)图中巨石的形成与下列哪个因素无关(  )&A.风化作用&&&& B.海蚀作用C.风蚀作用&&&& D.变质作用解析:变质作用是在地下高温高压作用下形成的,故无关。答案:D6.与流水作用相关的地貌类型是(  )①我国黄土高原的黄土堆积②东非大裂谷的形成 ③崇明岛的形成与扩大 ④塔里木盆地边缘的冲积扇A.①②& B.②③& C.③④& D.①④解析:黄土高原的黄土是风力堆积;东非大裂谷是内力作用(张裂);崇明岛与冲积扇都是流水沉积。答案:C7.下图是某旅行社制作的几幅宣传图片,据此完成(1)~(3)题。&(1)请你根据所学知识,正确搭配各图示景观的大致分布地区。a.长江三峡______& b.楼兰古城______c.天山一号冰川______& d.西北“魔鬼城”______e.“鱼米之乡”________& f.“黄土高坡”________答案:A C D F B E(2)请用地质作用解释各地貌景观的成因。A________________;& B________________;C________________;& E________________;F________________。答案:流水侵蚀 流水沉积 风力沉积 流水侵蚀 风力侵蚀(3)进一步给旅游参观者解说D图中①、②、③的具体名称。①是________,②是________,③是________。以上六种地貌形成的能量都来自________。答案:冰斗 角峰 U型谷 太阳辐射(或地球外部)&一、选择题1.(;汕头调研)在我国西北天山、昆仑山等山脉海拔3000米以上地区,常看到地表广泛分布着大量碎石的山体(见图3),该碎石的产生,最可能来自于(  )&A.流水侵蚀作用B.冰川侵蚀作用C.温差导致的风化作用D.人为破坏作用                解析:西北地区,昼夜温差大,风化作用强。答案:C2.(;肇庆调研)下图A为某地貌景观图,为解释该景观的部分成因,教师在教学时进行了如图B的演示,教师演示了(  )&A.板块挤压碰撞&&&& B.岩块断裂上升C.岩层水平挤压&&&& D.外力侵蚀搬运解析:该地貌为褶皱山,岩层水平挤压形成。答案:C读某种地形示意图,完成3~5题。&3.形成该种地形的主要原因是(  )A.冰川侵蚀作用&&&& B.流水侵蚀作用C.风力侵蚀作用&&&& D.地壳运动4.该种地形在我国哪个地区分布最为普遍(  )A.内蒙古高原&&&& B.青藏高原C.云贵高原&&&&&& D.黄土高原5.下列自然地理事物的形成与图示地形成因有密切联系的是(  )A.挪威西海岸幽深的峡湾B.科罗拉多大峡谷C.东非大裂谷D.雅鲁藏布大峡谷3~5.解析:本题组考查冰川地貌的成因及分布。从示意图中的“U型谷”、角峰可知,该地貌为冰川侵蚀地貌,分布在纬度较高或海拔较高的高原山地地区。挪威地处纬度较高的北欧,冰川地貌广布,由于冰川向前滑动时对地面有较大的刨蚀作用,故形成幽深曲折的峡湾;科罗拉多大峡谷是内外力共同作用形成的;东非大裂谷是板块张裂作用造成的;雅鲁藏布大峡谷主要是流水侵蚀作用形成的。答案:3.A 4.B 5.A6.下图为福建省南碇岛“规则多边形玄武岩石柱群”景观,它形成的主要地质作用是(  )&A.变质作用&&&& B.岩浆活动C.海浪侵蚀&&&& D.风化作用答案:B7.(;惠州调研)长江中游的荆江河段,因河道非常弯曲被称之为“九曲回肠”。形成这种景象的地质作用主要是(  )A.地壳的水平挤压&&&& B.河流的侵蚀、堆积C.地壳的断裂凹陷&&&& D.海水的搬运、侵蚀答案:B读某洞穴剖面景观示意图,完成8~10题。&8.图中所示的地形景观是在(  )A.石灰岩分布区B.花岗岩分布区C.玄武岩分布区D.砂岩分布区9.该地形景观在我国四大高原中有广泛分布的是(  )A.青藏高原& B.内蒙古高原C.云贵高原& D.黄土高原10.该洞穴所反映的各种地貌景观是由哪种地质作用形成的(  )A.风化作用&&&& B.侵蚀作用C.搬运作用&&&& D.堆积作用8~10.解析:根据图分析可知,该图为溶洞,属于喀斯特地貌,是石灰岩受含CO2的水溶蚀而成;溶洞内的石笋、钟乳石、石柱是由堆积作用形成的。答案:8.A 9.C 10.D11.下图为岩石圈物质循环示意图,下列说法正确的是(  )&A.图中箭头②表示外力作用,其余均为内力作用B.三大类岩石之间可直接相互转化C.三大类岩石和岩浆之间可直接相互转化D.只有岩浆岩在高温高压下,才可能形成变质岩解析:岩石圈物质循环过程中岩浆及三大类岩石间的转换关系是难点内容。岩浆岩只能由岩浆直接冷却凝固而形成;但各类岩石均可在岩石圈深处或岩石圈以下,发生重熔再生而成为新的岩浆;三类岩石均可能受外力作用最后固结成为沉积岩;已生成的各类岩石由于地壳运动和岩浆活动的影响,在一定温度、压力等条件下发生变质作用而成为变质岩;图中数码所代表的地质作用只有②属于外力的风化、侵蚀、搬运、堆积作用,①③④作用的能量来自地球内部,属内力作用。答案:A二、综合题12.下图是地貌形成与地质作用关系图。读图完成(1)~(4)题。&解析:本题组考查地质作用及其对地表形态的影响。崇明岛是流水堆积形成的,但其堆积物是从上游流水侵蚀形成,并从上游搬运而来的泥沙。青藏高原的不断升高是亚欧板块和印度洋板块碰撞挤压而成的;大兴安岭起伏和缓,证明存在外力的侵蚀作用。(1)将有关内容的数字代号填入下列相应的横线上:①变质作用& ②侵蚀作用③内力作用& ④外力作用⑤固结成岩作用A.________& B.________C.________& D.________E.________答案:④ ③ ②或⑤ ① ⑤或②(2)据研究,上海崇明岛在不久的将来可能与南通地区相连,形成该现象的主要外力作用是______、________和________。答案:流水侵蚀 流水搬运 流水堆积(3)变质作用的能量主要来自______________________________________;冰川作用的能量主要来自______________。答案:地球内部放射性元素衰变积累的能量 太阳能(4)地球地貌是在内外力共同作用下形成的,但有时内力作用占主导地位,有时外力作用占主导地位。试解释青藏高原不断升高、大兴安岭起伏和缓的原因。青藏高原:________________________________________________________________________。大兴安岭:________________________________________________________________________。答案:地壳不断上升,以内力作用为主 地壳不断遭受侵蚀,以外力作用为主13.读图,分析完成(1)~(4)题。&(1)图中A地貌类型主要分布于我国的________地区,是因为________作用强烈而形成。(2)图中F为流动沙丘,是由风力的________和______作用而形成的。(3)图中C为岩浆侵入地下而形成的花岗岩,在C岩体周围有可能形成________岩,C、E、D所代表的三种岩石,由老到新排列的顺序是________。(4)根据图示,该地区发生内力作用的主要表现形式有________、________和________。解析:A处地貌为风蚀蘑菇,是由风力侵蚀作用形成的风蚀地貌,在我国西北地区分布较广,岩层D覆盖在岩层E上,故岩层D比岩层E新,而C侵入岩层D、E中,故其比岩层D、E新。图中反映的地质作用既有岩浆活动、地壳活动、变质作用等内力作用,又有风力侵蚀、风力沉积、风化等外力作用。答案:(1)西北内陆 风力侵蚀(2) 搬运 沉积 (3)变质 E、D、C(4) 地壳运动 岩浆活动 变质作用
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必修一质点 参考系和坐标系练习题(含解析人教版)基础夯实一、选择题(1~3题为单选题,4、5题为多选题)1.(九江一中学年高一上学期期中)关于质点,下列说法中正确的是(  )A.评委为体操运动员刘璇的“跳马”动作评分,可将刘璇看作质点B.质点是一个理想化模型,但实际是存在的C.物理学中的“质点”跟几何学中的“点”没有区别D.如果物体的大小和形状在研究的问题中属于无关的或次要的因素,就可以把物体看做质点答案:D解析:当物体的形状、大小对我们所研究的问题影响不大,或者可以忽略时,物体可以看做一个有质量的点。评委需要根据体操运动员的动作情况打分,所以不能看做质点,A错误,D正确;质点是理想化的模型,现实中是不存在的,B错误;几何中的点没有质量,而质点是一个有质量的点,C错误。2.(宿迁市学年高一上学期检测)下列关于参考系的说法,正确的是(  )A.参考系是为了研究物体的运动而选取的B.看到从匀速飞行的飞机上落下的重物沿直线竖直下落,是地面上的人以地面做参考系观测到的结果C.只能选取静止不动的物体作为参考系D.同一个运动对不同的参考系,其观察结果一定是相同的答案:A解析:参考系是为了描述物体的运动而事先选来作为标准的物体,故选项A正确;参考系的选取是任意的,以对物体运动的描述尽可能简单为基本原则,故选项C错误;看到从匀速飞行的飞机上落下的重物沿直线竖直下落,是飞机上的人以飞机或自身做参考系观测到的结果,若地面上的人以地面做参考系观测的结果是该物体做抛物线运动,故选项B错误;由选项B的分析可知,同一个运动对不同的参考系,其观察结果可能不同,故选项D错误。3.在60周年国庆盛典上,游行的队伍和彩车依次从天安门前经过(如图),以北京长安街为坐标轴x,向西为正方向,以天安门中心所对的长安街中心为坐标原点O,建立一维坐标系,一辆彩车最初在原点以东3km处,一段时间后行驶到原点以西2km处。这辆彩车最初位置和最终位置分别是(  )&A.3km 2km &B.-3km 2kmC.3km -2km &D.-3km -2km答案:B解析:坐标轴的正方向向西,则位置在原点以西为正,在原点以东为负。彩车最初在原点以东且距原点3km处,所以最初位置是-3km,同理最终位置是2km,故B正确。4.(泰州市学年高一上学期期中)关于质点和参考系,下列说法中正确的是(  )A.质点就是体积很小的点B.研究人造地球卫星绕地球一周的时间时,卫星可以被看作质点C.“一江春水向东流”是以水为参考系来描述江水的运动D.我们常说“太阳东升西落”,是以地球为参考系描述太阳的运动答案:BD解析:一物体能否看成质点主要看物体的大小、形状在研究的问题中能否忽略,与物体自身的大小无关,所以A错误;卫星绕地球公转时,其大小、形状可以忽略,所以可以看作质点,故B正确;“一江春水向东流”是以岸或岸边树木为参考系来描述水的运动,所以C错误;我们常说“太阳东升西落”,是以地球为参考系描述太阳的运动,所以D正确。5.随着城市现代化的发展,电梯越来越多的出现在人们生活中,为大家带来了快捷和便利。而观光电梯是适应人们的进一步需求而产生的,乘坐人员可以观看电梯外面的景色,享受现代设备带来的视觉感受。正在乘坐电梯下楼的一位同学看到身旁的大楼拔地而起,大声惊叫:“楼不是静止的吗?怎么动起来了?”对于大楼的“运动”情况,下列说法正确的是(  )&A.楼只能是静止的,不可能运动B.楼实际在运动,不可能真的静止C.看到楼在运动是以乘坐的电梯为参考系D.看到楼静止是以地面(或地面上不动的物体)为参考系答案:CD解析:电梯向下运动过程中,距离地面越来越近,以电梯为参考系,感觉大楼是上升的,我们平时所说大楼是静止的,通常是以地面为参考系,A、B错,C、D对。二、非选择题6.从高出地面2m的位置竖直向上抛出一个球,它上升4m后回落,最后小球到达地面,如图所示,分别以地面和抛出点为原点建立坐标系,方向均以向上为正,填写下表:&坐标原点的设置&出发点的坐标&最高点的坐标&落地点的坐标以地面为原点&&&以抛出点为原点&&&答案:2m&6m&00&4m&-2m解析:本题比较灵活地考查了对坐标系的选取和理解。题中的物体沿直线运动,可以在该直线上建立直线坐标系来定量描述物体的位置,若以地面为原点,则出发点、最高点、落地点的坐标分别为:x1=2m,x2=6m,x3=0;若以抛出点为原点,则x′1=0,x′2=4m,x′3=-2m。7.研究火车的各种运动情况时(如图),哪些情况可以将火车视为一个质点?&答案:(1)(3)不可以看做质点,(2)可以看做质点。解析:(1)火车进站时,火车的长度与站台相比不能被忽略,所以在研究火车进站的时间时,不能将火车看做质点。(2)火车的长度与从北京到重庆的距离相比,可以忽略不计,所以在研究火车从北京到重庆的时间时,可以将火车看做质点。(3)研究火车车轮上某点的运动与车轮的大小和形状有关,这种情况下不能将火车看做一个质点。8.在我国东南部的一个大城市,有一天下午,该城市的中心广场行人拥挤,有一个人突然高喊“楼要倒了!”其他人猛然抬头观看也发现楼在慢慢倾倒,便纷纷狂奔逃生,引起交通混乱,但过了好久,高楼并没有倒塌,人们再仔细观望时,楼依然稳稳的矗立在那里,如图所示。请你探究分析这一现象的原因是什么?&解析:看到静止的楼在运动,应该是选择了运动的物体做参考系,高楼矗立在空中,以开阔的天空为背景的高层建筑,它旁边没有别的固定的参考系,人在抬头观望时可能是选择了空中运动的云做参考系,如果天空的云在快速移动,人在突然抬头观望时,误将云看做是固定不动的,所以产生了楼在运动的错觉。能力提升一、选择题(1~3题为单选题,4、5题为多选题)1.公路上一辆卡车紧急刹车,由于惯性,卡车上的货物相对车厢向前滑行了x=15mm,为了测出这个距离x,我们选择的最合理的参考系应该是(  )A.树木  &B.卡车  C.行人  &D.公路答案:B解析:滑行了15mm是相对于卡车车厢,测这个滑行距离,选卡车为参考系最为方便,B对。2.一个小球从距地面4m高处竖直向下抛出,被地面弹回,在距地面1m高处被接住。坐标原点定在抛出点正下方2m处,向下方向为坐标轴的正方向。则小球的抛出点、落地点、接住点的位置坐标分别是(  )A.2m,-2m,-1m &B.-2m,2m,1mC.4m,0m,1m &D.-2m,0m,-1m答案:B解析:解答本题的关键是正确地建立坐标系,并在坐标系中标出各个时刻对应的位置。根据题意建立如图所示的坐标系,A点为抛出点,坐标为-2m,B点为坐标原点,D点是地面,坐标为2m,C点为接住点,坐标为1m,所以选项B正确。3.一只蜜蜂和一辆汽车在平直公路上以同样的速度并列运动。如果这只蜜蜂的眼睛紧盯着车轮边缘上某一点,那么它看到的这一点的运动轨迹应是下图中的(  )&答案:A解析:蜜蜂、汽车车身向前具有相同的速度,它们是相对静止的,所以蜜蜂看不到轮子向前运动,只能看到轮子的转动,故A正确。4.(河北冀州中学学年高一上学期期中)如图是某次日全食时的美妙景象,那么下列说法正确的是(  )&A.在观测日全食时可将月亮看成质点B.在观测日全食时不能将月亮看成质点C.月亮绕地球转动,这是以太阳为参考系来描述的D.月亮绕地球转动,这是以地球为参考系来描述的答案:BD解析:物体的大小和形状对所研究问题的影响可以忽略不计的情况下,可以把物体看成质点,所以在观测日全食时不能将月亮看成质点,A错,B对。在地球上的人观察月亮绕地球做圆周运动,是以地球为参考系来描述的,C错,D对。5.(潍坊城区学年高一上学期检测)如图所示,由于风,河岸上的旗帜向右飘,在河面上的两条船上的旗帜分别向右和向左飘,两条船的运动状态是(  )&A.A船可能是向右运动的 &B.A船肯定是静止的C.B船肯定是向右运动的 &D.B船可能是静止的答案:AC解析:(1)A船运动情况的确定:由题图知A船与河岸上的旗帜均向右飘,则相对于风,A船、河岸都具有向左的运动速度,所以A船可能相对河岸静止,也可能以任意速度向左运动,还有可能以相对比风速小的速度向右运动。A正确,B错误。(2)B船运动情况的确定:B船中旗帜向左飘,表明B船只能向右运动,且速度大于风速,C对,D错。二、非选择题6.公路上向左匀速行驶的汽车如下图甲,经过一棵果树附近时,恰有一颗果子从上面自由落下,图乙是其运动的轨迹。则地面上的观察者看到的运动轨迹是________,车中人以车为参考系看到的果子的运动轨迹是________。(不计阻力)&    图甲           图乙   答案:C B解析:果子从树上自由下落相对地面是直线运动,故地面上的观察者将看到轨迹C。车内的乘客以车为参考系,果子下落的同时,将相对车向右运动,故其看到的轨迹应是B。7.伦敦奥运会冠军、美国名将苏尔在美国室内撑杆跳比赛中(如图),以5米02的成绩,打破了俄罗斯选手伊辛巴耶娃创造的5米01的世界纪录。撑杆跳高是一项非常刺激的体育运动项目,一般来说可以把撑杆跳高运动分为如下阶段:助跑撑杆起跳、越过横杆。讨论并思考后回答,在下列几种情况下运动员能否被看作质点。从中体会质点模型的建立过程。&(1)教练员针对训练录像纠正运动员的错误时,能否将运动员看成质点?(2)分析运动员的助跑速度时,能否将其看成质点?(3)测量其所跳高度(判断其是否打破记录)时,能否将其看成质点?答案:(1)不能 (2)能 (3)能解析:(1)纠正错误动作时不能忽略运动员的姿势及动作,也就是说不能忽略运动员的形状和大小。(2)分析助跑速度时,可以忽略运动员的姿势及动作。此时姿势和动作对研究速度没有影响。(3)只要看能否越过横杆即可。8.如图所示,一条绳子长1.5m,放在高0.8m的桌子上,有一部分悬在桌外,留在桌面上的部分长1.2m,以地面上的一点O为坐标原点,竖直向上为正方向,求绳的最低端的坐标。&答案:0.5m解析:由题图可知,悬在桌外的绳长为:O′B=1.5m-1.2m=0.3m。B点到O点的距离为:OB=OO′-BO′=0.8m-0.3m=0.5m。若以O点为坐标点,以OO′为正方向,以1m为单位长度,则B点的坐标为0.5m。&
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高一地理必修一第1章行星地球知识总结(带答案人教版)&&&&&&&&&&&&&&&&&& &&1.光照图的类型(1)地球公转轨道图。在地球公转轨道图中,完整展现二分二至日的光照图,一般结合地轴方向、近日点、远日点进行判读。&(2)公转轨道局部图。结合公转方向和昼夜分布判读。下图中阴影为夜半球,太阳直射在赤道上,之后太阳直射点向南移动,可确定为9月23日左右的光照图。&(3)地球侧视图。这是最常见的一种日照图,一般北极在上,南极在下,赤道为一直线居中,地轴或垂直或倾斜,晨昏线为直线,与太阳光线垂直,并平分赤道。二分日时,晨昏线起止于南北两极;二至日时,晨昏线起止于南北极圈相切的两切点,除二分日以外的时间,晨昏线与极地的某纬线圈(纬度度数相同)相切。&(4)极地俯视图。中心为极地,外圆为赤道。分北极图和南极图。二分日时,晨昏线为直线,与太阳光线垂直,且通过南北两极点;二至日时,晨昏线为弧线且与南北极圈相切。&(5)斜侧(俯)视图。观测点既不在赤道上空,也不在极点上空,观测到的光照情况即为斜侧(俯)视图。&(6)矩形投影图。矩形投影图是将南北极点、南北极圈、南北回归线放大到与赤道一样长,它与实际图相比有很大的变形,离赤道越远,变形越大。判读此类图的关键是晨昏线、极昼极夜和赤道上的日出(6点)、日落(18点)时间等。&2.光照图的判读及应用通常依据以下方式去解读光照图:(1)南北半球的确定。对于侧视图,通常是上北下南,而对于俯视图或有关变式图,根据地球自转的方向来判断南北半球是常用的有效方法。(2)确定方向。光照图常常与经纬网图一并出现。根据晨昏线先确定地球自转的方向和东西经度,然后根据经线确定南北方向,根据纬线确定东西方向。最后根据要求确定两点的相对方向。&(3)依据地球自转方向确定晨线和昏线或依据晨线或昏线确定地球自转方向。晨昏线上的点随地球自转进入昼半球则该线为晨线,反之为昏线;晨线上将进入昼半球的方向为地球自转方向,昏线上将进入夜半球的方向为地球自转方向。(4)确定太阳直射点的位置。太阳高度由直射点向四周逐渐降低,直射点的太阳高度为90°,晨昏线上为0°。直射点位于昼半球的中心。由此推断其所在的经度和纬度,即俯视图上直射点是平分昼半球的那条经线的经度(注意东西经);纬度按极昼、极夜之间的平分线来确定(注意南北纬)。纬度也可根据与晨昏线相切的纬线求出,即太阳直射点纬度=90°-相切点所在的纬度。(直射点与发生极昼的地区在同一半球)(5)确定地方时。要把握住光照图中隐含的时间信息:①赤道与晨线的交点所在经线的地方时为6时,与昏线交点所在经线的地方时为18时;②太阳直射点所在的经线(或昼半球的中央经线)地方时为12时,夜半球的中央经线地方时为0时。(6)确定日期。①晨昏线通过南北极可断定这一天是3月21日或9月23日前后,进而再根据其他条件进一步判断。②晨昏线与南北极圈相切,北极圈内皆为昼弧,可断定这一天是6月22日,北半球夏至日,北半球为夏季,南半球为冬季。③晨昏线与南北极圈相切,北极圈内皆为夜弧,可断定这一天是12月22日,北半球冬至日,北半球为冬季,南半球为夏季。(7)昼夜长短及日出日落时间的判定。①昼夜长短的纬度变化。太阳直射点位于北半球,则北半球各地昼长夜短,越往北昼越长,北极地区出现极昼,极昼范围是北纬(90°-直射点的纬度数)及以北地区;南半球各地昼短夜长,越往南,夜越长,南极地区出现极夜,极夜范围是南纬(90°-直射点的纬度数)及以南地区。太阳直射点位于南半球则相反。②昼夜长短的季节变化。太阳直射点向北移动,则北半球各地昼渐长,夜渐短;南半球各地昼渐短,夜渐长。太阳直射点向南移动,则南半球各地昼渐长,夜渐短,北半球各地昼渐短,夜渐长。无论太阳直射点怎样移动,赤道上终年昼夜等长。③晨昏线与经线圈重合,判断某地日出日落时间和昼长夜长。晨昏线是日出日落线,春秋二分日晨昏线通过两极,与经线圈重合,因此各条纬线上的日出日落时刻都是相同的,即各地地方时6时日出,18时日落,昼夜平分,都为12小时。④晨昏线与经线斜交,推算某地昼长或夜长和日出日落时间。推算某地昼长或夜长,求昼长时,在昼半球范围内算出该地所在的纬线圈从晨线与纬线圈交点开始到昏线与纬线圈交点,所跨的经度差除以15°即为该地昼长。12-昼长/2=日出时间,12+昼长/2=日落时间。& 下图为某日部分地区昼夜示意图,阴影部分表示黑夜,其余部分表示白昼。读图完成(1)~(4)题。&(1)按东、西半球划分,图上阴影部分主要位于______半球,此时甲地地方时是______点。(2)按南、北半球划分,此时太阳直射点位于______半球,太阳直射点的经度是______。(3)该日乙地的白昼时间长约________小时。(4)如果晨昏线与甲地所在经线的夹角为10°,则该日正午时分上海(31°N)世博园场馆的太阳能电池板与建筑物外墙面(墙面与地面垂直)之间最合适的夹角约为________。解析:(1)由图中经度变化规律可知,图中经度为西经度,再根据东西半球的划分依据也知为西半球。甲为晨线与赤道的交点,其地方时为6时。(2)由图中晨昏线与经线相交关系可判断太阳直射点在北半球。甲地位于37.5°W与22.5°W之间的中点位置,故可推知甲地经度为30°W,由上题可知甲地地方时为6时,而太阳直射点的地方时为12时,由此可算出太阳直射点的经度为60°E。(3)甲地为30°W,地方时为6时,乙地经度为22.5°W,即可算出乙地地方时为6:30,而乙地正好位于晨线上,即可知乙地该日6:30日出,再根据昼长=(12时-日出时间)×2,即可算出乙地白昼时间长约11小时。(4)由题可知该时太阳直射点位于10°N,再根据正午太阳高度的计算公式,可算出该日上海正午太阳高度为69°,由此推出,太阳能电池板与建筑物外墙面之间最合适的夹角约为69°。答案:(1)西 6 (2)北 东经60°(3)11 (4)69°&
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必修一时间和位移测试题(附解析人教版)基础夯实一、选择题(1~3题为单选题,4、5题为多选题)1.关于时刻和时间,下列说法正确的是(  )A.作息时间表上的数字均表示时间B.1min只能分成60个时刻C.手表上指针指示的是时间D.“宁停三分,不抢一秒”指的是时间答案:D解析:作息时间表上的数字表示的是起床、就餐、上下课的时刻,A错。1min能分成无数多个时刻,B错。手表上指针指示的是时刻,C错。“宁停三分,不抢一秒”指的是时间,D对。2.(南昌市学年高一上学期期中)某质点向东运动12m,又向西运动20m,又向北运动6m。则在上述过程中它运动的路程和位移的大小分别是(  )A.38m,10m       &B.2m,10mC.14m,6m &D.38m,6m答案:A解析:路程是运动轨迹的长度,所以路程为38m,位移是初位置指向末位置的有向线段,线段的长度表示位移的大小,所以位移大小为10m。3.关于矢量和标量,下列说法中错误的是(  )A.矢量是既有大小又有方向的物理量B.标量是只有大小没有方向的物理量C.位移-10m比5m小D.-10℃比5℃的温度低答案:C解析:由矢量和标量的定义可知,A、B正确;-10m的位移比5m的位移大,负号不表示大小,仅表示方向与正方向相反,故C错误;温度是标量,-10℃比5℃的温底低,负号表示该温度比0℃低,正号表示该温度比0℃高,故D正确。4.(青岛市学年高一上学期检测)日,海军第十六批护航编队从青岛某军港解缆启航,奔赴亚丁湾、索马里海域执行护航任务,编队由导弹护卫舰“盐城舰”和“洛阳舰”、综合补给舰“太湖舰”组成,此次护航总航程5300海里,若三只舰艇运动速度相同,则下列说法正确的是(  )&A.“5300海里”指的是护航舰艇的位移B.“5300海里”指的是护航舰艇的路程C.研究“盐城舰”从青岛到亚丁湾的路线时可把它视为质点D.以“太湖舰”为参考系,“盐城舰”和“洛阳舰”都在运动答案:BC解析:“5300海里”指的是舰艇的航行路程,A错,B对;研究舰艇的航行路线时可将其视为质点,C对;因三只舰艇的运动速度相同,故D选项错误。5.某学校田径运动场跑道示意图如图所示,其中A点是所有跑步项目的终点,也是400m、800m赛跑的起点;B点是100m赛跑的起跑点,在校运动会中,甲、乙、丙三个同学分别参加了100m、400m和800m比赛,则(  )&A.甲的位移最大 &B.丙的位移最大C.乙、丙的路程相等 &D.丙的路程最大答案:AD解析:甲同学的初、末位置直线距离为100m,位移大小为100m,路程也是100m;乙同学路程为400m,但初、末位置重合,位移大小为零,丙同学路程为800m,初、末位置重合,位移大小也为零,所以甲的位移最大,丙的路程最大,A、D项正确。二、非选择题6.阅读下面的对话:甲:请问到市图书馆怎么走?乙:从你所在的市中心向南走400m到一个十字路口,再向东走300m就到了。甲:谢谢!乙:不客气。请你在下图上把甲要经过的路程及位移表示出来,并求出大小。&答案:甲的路程为400m+300m=700m(图中虚线所示)甲的位移为x=m=500m(图中有向线段所示)路程与位移表示如下图所示。&7.如图所示,一辆轿车从超市出发,向东行驶了300m到达电影院,继续行驶了150m到达度假村,又向西行驶了950m到达博物馆,最后回到超市。以超市所在的位置为原点,以向东的方向为正方向,用1个单位长度表示100m,试求:&(1)在直线坐标系上表示出超市、电影院、度假村和博物馆的位置;(2)轿车从电影院经度假村到博物馆的位移与路程分别为多少?答案:(1)如图:&(2)800m,方向向西 1100m解析:(1)见答案(2)轿车从电影院经度假村到博物馆的位移为x=-500m-300m=-800m,负号表示其方向与规定的正方向相反,即方向向西。其路程为l=150m+450m+500m=1100m。能力提升一、选择题(1、2题为单选题,3、4题为多选题)1.关于时刻和时间间隔,下列说法正确的是(  )A.老师说:“明天早上8点钟上课,上课45分钟。”其中“8点钟上课”指的是时间,“上课45分钟”指的是时刻B.小王迟到了,老师对他说:“为什么你现在才来?你早该到校了。”其中“你早该到校了”指的是到校的时间间隔C.小王说:“我早已从家里出来了,因为今天公共汽车晚点了。”其中“早已从家里出来了”指的是时间间隔D.老师说:“希望你下次一定要在7点50分以前到校。”其中“7点50分以前”指的是时间间隔答案:D解析:关于时刻和时间间隔,一定要抓住最主要的问题。时刻对应时间轴上的一个点;而时间间隔则对应时间轴上的一段,即一段时间。在A选项中“8点钟上课”对应时间轴上的一个点,即上课开始的时刻,而“上课45分钟”指的是上课所经历的时间,它对应时间轴上的一段,即时间间隔,因此A错误。在B选项中“你早该到校了”指的是小王应该到校的时刻,对应时间轴上的点,因此B错误。在C选项中“早已从家里出来了”指的是从家里出来的时刻,对应时间轴上的一个点,因此C错误。在D选项中“7点50分以前”对应时间轴上的一段,即时间间隔,因此D正确。2.一支长150m的队伍匀速前进,通信兵从队尾前进300m后赶到队首,传达命令后立即返回,当通信兵回到队尾时,队伍已前进了200m,则在此全过程中,通信兵的位移大小和通过的路程分别是(  )A.150m 300m &B.200m 300mC.150m 400m &D.200m 400m答案:D解析:根据题意队伍行驶,通信兵运动的草图可用下图所示。&取原来通信兵所在队尾为参考点,即O点为参考点,通信兵运动轨迹可表示为图中从O点到A点再回到B点。因此通信兵的位移x=OB→,路程L=OA→+AB→。由图可知:OB=200m,AB=100m所以通信兵位移x=200m,路程L=300m+100m=400m。3.(淄博市学年高一上学期期中)下列关于位移和路程的说法中正确的是(  )A.路程是标量,只有大小;位移是矢量,有大小也有方向B.物体沿直线运动,通过的路程一定等于位移大小C.物体两次通过的路程不等,位移可能相等D.物体通过一段路程,则它通过的位移不可能为零答案:AC解析:位移是指由初位置指向末位置的有向线段,而路程是指物体运动轨迹的长度,因此物体可以沿不同的路径从一点运动至另一点,即位移相等,而路程不同,故选项C正确;如果物体运动一圈绕回原出发点,则位移为零,而路程不为零,故选项D错误;路程是标量,只有大小,没有方向,位移是矢量;既有大小又有方向,故选项A正确;只有物体沿直线作单向运动时,通过的路程才等于位移大小,其它情况下,通过的路程总大于位移大小,故选项B错误。4.物体做直线运动时可以用坐标轴上的坐标表示物体的位置,用坐标的变化量Δx表示物体的位移。如图所示,一个物体从A运动到C,它的位移Δx1=-4m-5m=-9m;从C运动到B,它的位移为Δx2=1m-(-4m)=5m。下列说法中正确的是(  )&A.C到B的位移大于A到C的位移,因为正数大于负数B.A到C的位移大于C到B的位移,因为符号表示位移的方向,不表示大小C.因为位移是矢量,所以这两个矢量的大小无法比较D.物体由A到B的位移Δx=Δx1+Δx2答案:BD解析:位移是位置坐标的变化量,位移的符号仅表示方向,不表示大小,故B正确,A、C错误,由位移公式可知D正确。二、非选择题5.下表是列车时刻表的部分片段,请回答以下几个问题:(1)表中所列数据是时刻还是时间间隔?(2)T15列火车在长沙站上停留了多少时间?(3)正常情况下,T16列火车从广州行驶到北京用多长时间?T15&站台&T1618:19&北京西&14:580:350:41&郑州&08:4208:3605:4905:57&武昌&03:2803:2009:1509:21&长沙&23:5925:5116:25&广州&16:52答案:(1)时刻 (2)6分钟 (3)22.1小时解析:(1)表中所列数据是火车到达和离开各个车站的时刻。(2)T15列火车在长沙站上停留的时间为t1=9h 21min-9h 15min=6min,即在长沙站上停留了6分钟。(3)正常情况下,T16列火车从广州行驶到北京用时t2=24h-16h 52min+14h 58min=22h 06min=22.1h即火车从广州行驶到北京要用22.1小时。6.一位电脑动画爱好者设计了一个“猫捉老鼠”的动画游戏,如图所示,在一个边长为a的大正方体木箱的一个顶角G上,老鼠从猫的爪间逃出,沿着木箱的棱边奔向洞口,洞口在方木箱的另一顶角A处。若老鼠在奔跑中,并不重复地跑过任意一条棱边,也不再回到G点,聪明的猫选择一条最短的路线奔向洞口(设猫和老鼠同时从G点出发)。结果猫再次在洞口A捉到了老鼠,问:&(1)老鼠的位移大小及最短路程是多少?(2)猫的位移大小和路程是多少?答案:(1)3a 3a (2)3a 5a解析:(1)经分析可知,老鼠从顶点G出发走过的最短路程为x=3a。质点的位移总是从初位置指向末位置,即为立体图中的AG两点间的距离。如图甲所示,AH=BG=2a,AG=GH2+AH2=3a。&(2)猫选择的是最短路线,猫所走的必须是一条直线,为了找到这条直线,可将木箱的两个面展开,如图乙所示,则路程为AG的长度。AG=a2+2a&#a。猫与老鼠同时从G点沿不同路径到达同一点A,所以位移相同。&
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