有这样一道计算题:“计算(2x³－3x²y－2xy²）－（x³－2xy²＋y³）＋（－x&su甲同学把x=1/2错看成x=－1/2,但计算结果仍正确,你说是怎么一回事?后面是＋（-x³+3x²y-y³）
化简后结果为-2y³
这种题应该这样想,如果x=½错看成x=-½,但计算结果仍正确,那么,原式有三种可能： 1化简后的式子不含X 2化简后X含x的项是一个平方项 3化简后的式子可能为常数项,那么该式无论未知数取什么,都是一个定值
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If you have trouble downloading this track, right-click the DOWNLOAD button above and choose "Save As..."解方程：1。x²+4x+2=0 2。x²-2x-3=0, 解方程：1。x²+4x+2=0 2。
解方程：1。x²+4x+2=0 2。x²-2x-3=0
轩dg 解方程：1。x²+4x+2=0 2。x²-2x-3=0
x²+4x+2=0x&sup锭担赤杆俦访稠诗椽涧2;+4x+4=2(x+2)²=2x+2=±√2x=-2-√2,x=-2+√2x²-2x-3=0 (x-3)(x+1)=0x=3,x=-1
1.x^2+4x+2=0x^2+4x+4=2(x+2)^2=2x=-2±√22.x^2-2x-3=0(x-3)(x+1)=0x=3或x=-1
。x²+4x+2=0
解： x²+4x=0+2
x²+4x=2
x=0.5 x²-2x-3=0 (x-3)(x+1)=0x=3,x=-1
x²+4x=2以下试题来自：
单项选择题已知圆C与圆：x2+y2-2x+2y=0关于直线x+y+2=0对称，则圆C的方程表达式为______。A．(x+1)2+(y+3)2=2 B．(x-1)2+(y+3)2=2C．(x+1)2+(y-3)2=2 D．(x-1)2+(y-3)2=2
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Uq(sl2)在Cq[x+-1,y]上的模代数结构
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