计算题4、 求y=2已知双曲线y x分之k1ln(1+x...

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高中导数计算题，求过程答案！1.y=（x的m次方+nx的n次方+n次根号下x）/x2.y=1/（1-根号x） + 1/（1+根号x）3.y=sin平方ax乘以cosbx4.y=三次根号下 x平方/1-x5.y=ln（1+a的-2x次方）6.y=ln（1+x）-x平方/4 7.y=x（1-x）平方要过程 谢谢~
xbMD23JA76
用求导公式嘛,过程还怎么说?
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出门在外也不愁444.　求下列函数的导数:(1) y=x3-3x2+4x-5；　　　　　　(2) ；(3) y=5x3-2x+3ex；(4) y=2tan?x+sec?x-1；(5) y=ln?x-2lg?x+3log2x；(6) y=sin?xcos?x；(7) y=x2ln?x；(8) y=3excos?x；(9) y=(2+3x)(4-7x)；(10) y=；(11) y=；(12) ；(13) ；(14) ；(15) ；(16) y=x2lnxcos?x；(17) ；(18) ；(19) ；(20) ；(21) y=；(22) y=e-x；(23) .
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解　(1) y′=3x2-6x+4.　　　　(2) y′=-20x-6-28x-5+2x-2.(3) y′=15x2-2xln?2+3ex.(4) y′=2sec2x+sec?xtan?x.(5) .(6) .(7) y′=2xln?...
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传真：010-Superconducting bismuth and thallium cuprates of the type $Bi_{2-x}Pb_x(Ca,Sr,Y)_{n+1}Cu_nO_{2n+4+\delta} (Tl,Pb)(Ca,Ln)(Sr,Ba)_2Cu_2O_{6+\delta}$ and $Tl(Sr,Ln)_{n+1}Cu_nO_{2n+3+\delta}$
Superconducting bismuth and thallium cuprates of the type $Bi_{2-x}Pb_x(Ca,Sr,Y)_{n+1}Cu_nO_{2n+4+\delta} (Tl,Pb)(Ca,Ln)(Sr,Ba)_2Cu_2O_{6+\delta}$ and $Tl(Sr,Ln)_{n+1}Cu_nO_{2n+3+\delta}$.
In: Diffusion and Defect Data - Solid State Data, Part A (Defect and Diffusion Forum), 2-3 Oct. 1989, Indianapolis, IN, USA, pp. 1-18.
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In the $Bi_{2-x}Pbx(Ca,Sr)_{n+1}Cu_nO_{2n+4+\delta}$ system, the superconducting properties of the n=1 to 4 members was established. The $T_c$ in this system increases from n=1 to 3 and does not increase further when n=4. In oxygen-annealed $Bi_2Ca_{1-x} Y_xSr_2Cu_2O_y$, the $T_c$ decrease in samples prepared in air or in a $N_2$ atmosphere, there is an increase in $T_c$ with x up to 0.25. Such electron-induced enhancement of $T_c$ is of interest. In $TlCa_{1-x}Ln_xSr_2Cu_2O_{6+\delta}$, electron- or hole-superconductivity was found to depend on x. $TI_{1-x}Pb_xCaSr_2Cu_2O_{6+\delta}$ shows clear evidence of electron superconductivity. $Tl(Sr,Ln)_{n+1}Cu_nO_{5+\delta}$ (n=1 and 2) superconductors containing neither Ca nor Ba have been characterized for the first time.
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high-temperasuperconducting tr thallium compounds
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16 Jan 2008
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